# What is the equation of the line that is normal to #f(x)= (x-3)^2+x^2-6x# at # x=0 #?

##### 1 Answer

Jan 6, 2016

y-9=

#### Explanation:

For given f(x), f '(x)= 2(x-3) +2x-6. Slope of tangent to f(x), at x=0 would be = -12. Therefore slope of the normal line would be